sin4x+cos4x=1-2sin2xcos2x
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Answered by
46
LHS- sin4x + cos4x
= (sin2x)2 + (cos2x)2
= (sin2x + cos2x)2 - 2sin2xcos2x {since a2 +b2 = (a+b)2 - 2ab}
= 12 - 2sin2xcos2x {since sin2x +cos2x = 1}
= 1 - 2sin2xcos2x
= RHS
hope helpful for u
= (sin2x)2 + (cos2x)2
= (sin2x + cos2x)2 - 2sin2xcos2x {since a2 +b2 = (a+b)2 - 2ab}
= 12 - 2sin2xcos2x {since sin2x +cos2x = 1}
= 1 - 2sin2xcos2x
= RHS
hope helpful for u
Answered by
77
Hey !!!
Sin⁴x + cos⁴x
=( Sin²x)² +( cos²x)²
•°• a² + b² = (a + b)² - 2ab
Like that .
=( Sin²x + cos²x )² - 2sin²x cos²x
= 1² - 2sin²x cos²x
= 1 - 2sin²x cos²x
Hope it helps you !!!
#Rajukumar111@@@@
Sin⁴x + cos⁴x
=( Sin²x)² +( cos²x)²
•°• a² + b² = (a + b)² - 2ab
Like that .
=( Sin²x + cos²x )² - 2sin²x cos²x
= 1² - 2sin²x cos²x
= 1 - 2sin²x cos²x
Hope it helps you !!!
#Rajukumar111@@@@
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