sin4x+cos4x=1 prove......
Answers
Answered by
0
sin⁴x+cos⁴x = 1
consider sin⁴x+cos⁴x =LHS
(sin²)²x+(cos²)²x
[Since, sin²#+cos²# =1,, where #=theta]
hence, (sin²)²x+(cos²)²x =1
Hence proved!!
consider sin⁴x+cos⁴x =LHS
(sin²)²x+(cos²)²x
[Since, sin²#+cos²# =1,, where #=theta]
hence, (sin²)²x+(cos²)²x =1
Hence proved!!
Answered by
0
Here is your answer
Attachments:
Similar questions