sin4x+sin2x=0 find the general solution
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Step-by-step explanation:
2sin 2xcos 2x + sin 2x =0
sin2x(2cos 2x +1)=0
sin2x=0 , so 2x=2npi
so x=npi
cos 2x= -1/2 , cos 2x= cos 2n(4pi/6)
x= n 2pi/3
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