Question

sin50/cos40+cosec40/sec50-4cos52•cosec38

Answer 1

heya
see the attachment
hope it helps u

Answer 2

◀ HERE'S ⏬ YOUR ANSWER▶

$\frac{sin50}{cos40} + \frac{cosec40}{sec50} - 4.cos52.cosec38 \\ = \frac{sin(100 - 40)}{cos40} + \frac{cosec(90 - 50)}{sec50} - 4.cos(90 - 38).cosec38 \\ = \frac{cos40}{cos40} + \frac{sec50}{sec50} - 4.sin38.cosec38 \\ = 1 + 1 - 4 \\ = - 2$

⏏HOPE THIS ⬆ HELPS YOU⏏