Math, asked by avi174, 1 year ago

sin58sin13+scos58cos13

Answers

Answered by vyas03

1

it is in the form of
cos(A-B) = sinAsinB+cosAcosB
clearly here A=58,B=13
cos(58-13) = cos45° = 1/√2
hence the answer is 1/√2

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