[(sin60/cos45)-3tan30+5cos90
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Answer:
(3√2-6)/2√3
Step-by-step explanation:
sin60=√3/2
cos45=1/√2
tan30=1/√3
cos90=0
So
replacing values in question we get,
[(√3/2/1/√2)-3(1/√3)+5(0)
=√6/2-3/√3+0
=(3√2-6)/2√3
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