Sin60cos30+sin30cos60
guriji:
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sin 60° cos 30°+sin 30° cos 60°=sin 60°sin(90°-30°)+cos(90°-30°)cos 60°
=sin²60°+cos²60°
=1 [∵sin²A+cos²A=1]
Hope it helps u :-)
=sin²60°+cos²60°
=1 [∵sin²A+cos²A=1]
Hope it helps u :-)
Answered by
2
Hey frnd
Here we have to use identity
Sin(A+B) =SinACosB+CosASinB
Sin(60°+30°)
= Sin60°Cos30°+ Sin30°Cos60°
Sin90°= Sin60cos30+sin30cos60
Sin60°Cos30°+ Sin30°Cos60 =1
Here we have to use identity
Sin(A+B) =SinACosB+CosASinB
Sin(60°+30°)
= Sin60°Cos30°+ Sin30°Cos60°
Sin90°= Sin60cos30+sin30cos60
Sin60°Cos30°+ Sin30°Cos60 =1
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