State the law was used to find specific heat of lead shots
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Ahoy !
We can use the law of equipartion of energy to determine specific heat of solids .
Consider one gram mole of the lead contaning Na atoms .
Each atom vibrates about its mean position . According to the law of equiparrition energy , avg energy associated with atom due to its oscillation in one dimension
= 2× 1/2 x kbT
avg energy = 3 x kb x T
Total energy of one gram mole
U = 3 x kb x T x Na
= 3 RT
Acc to firsr law of thermo
dQ = dU + dW
= dU + PdV
For solids dV is negligible
dQ = dU
C = dQ / dT
C = dU / dT
dQ= 4.184 J
dT = 1 C
C= 4.184 / 1
Now The Value of the specific heat of the Pb = 4.184 J/ gC
May it helps you ^ _ ^
We can use the law of equipartion of energy to determine specific heat of solids .
Consider one gram mole of the lead contaning Na atoms .
Each atom vibrates about its mean position . According to the law of equiparrition energy , avg energy associated with atom due to its oscillation in one dimension
= 2× 1/2 x kbT
avg energy = 3 x kb x T
Total energy of one gram mole
U = 3 x kb x T x Na
= 3 RT
Acc to firsr law of thermo
dQ = dU + dW
= dU + PdV
For solids dV is negligible
dQ = dU
C = dQ / dT
C = dU / dT
dQ= 4.184 J
dT = 1 C
C= 4.184 / 1
Now The Value of the specific heat of the Pb = 4.184 J/ gC
May it helps you ^ _ ^
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