Question

sin65° /sin25°+ cos32°/sin58°-sin28°*sec62°+cosec²30°


pls fast without using trigonometry tables

Answer 1

Sin(90-a)=cos a---------(1)

Cos (90-a)= sin a-------(2)&

Sec a= 1/cos a

Also we'll use the value of standard angle cosec30 I.e 2

Sin(90–25)/cos 25 +cos(90–58)/sin 58 -sin(90–62) × 1/cos 62 +cosec²30 —(1&2)

Cos25/cos 25 + sin58/sin58 -cos62/cos62 +4(standard angle cosec²30=2²=4)

1+1–1+4

5(ans) 

Thanks to quora user Raghav Tripathi