Question

Sin⁶A+Cos⁶A+3Sin²A×Cos²A=​

Answer 1

Answer:

Step-by-step explanation:

sin^6A+cos^6A

(sin²A)³+(cos²A)³ ............[a^6=(a²)³]

(sin²A+cos²A)³-3sin²Acos²A.........[(a+b)³=a³+b³+3ab]

1³-3sin²Acos²A

1-3sin²Acos²A

!!hence proved!!