Question

sin6A +cos6A + 3sin²A.cos²A=? 6 is the power of sin And cos, can't be typed as so​

Answer 1

Answer:

Step-by-step explanation:

Consider LHS:

sin6A+cos6A = (sin2A)3 + (cos2A)3

                    = (sin2A + cos2A)3 − 3 sin2A cos2A(sin2A + cos2A)  [Since, (a+b)3

= a3 + b3 +3ab(a+b)]

                    = (1)3 − 3 sin2A cos2A(1)  [Since, sin2A + cos2A = 1]

                    =   1 − 3 sin2A cos2A

                    = RHS