sin6x cos5x dx]
\limits^a_b {x} \, dx [/tex]
Answers
Answered by
0
looks like the problem is integration of Sin 6x Cos 5x
f(x) = Sin 6x Cos 5x = 1/2 [ Sin 11 x + Sin x ]
Integration of f(x) with respect to x gives us
- 1/22 Cos 11x - 1/2 Cos x + K
f(x) = Sin 6x Cos 5x = 1/2 [ Sin 11 x + Sin x ]
Integration of f(x) with respect to x gives us
- 1/22 Cos 11x - 1/2 Cos x + K
Similar questions