Question

sin6x + sin 4x sin2x = 4cosx sin2x cos3x​

Answer 1

Step-by-step explanation:

hope it will help you ☺️

Answer 2

Hence proved.

Step-by-step explanation:

Given;

Simplify; $sin6x + sin 4x -sin2x = 4cosx\, sin2x \,cos3x$

∴ LHS:

$sin6x + sin 4x -sin2x$

$=2sin\frac{6x+4x}{2}cos\frac{6x-4x}{2}-sin2x$

$=2sin5x\,cosx-2sinx\,cosx$

$=2cosx(sin5x-sinx)$

$=2cosx \,2cos\frac{5x+x}{2} sin\frac{5x-x}{2}$

$=4cosx\,cos3x\,sin2x$

$=4cosx\,sin2x\,cos3x$

$=$RHS

Hence proved.