Math, asked by narendralohiya007, 1 month ago

sin⁸A-cos⁸A=(sin²A-cos²A)(1-2sin²Acos²A)​

Answers

Answered by llMagicLilyll
5

Answer:

To prove :

sin³A - cos³ A

= (2 sin²A - 1)(1-2 sin²A cos²A)

Proof:

Now, sin³A - cos³ A

= (sin A - cos*A) (sin*A + cos*A)

= (sin³A + cos²A) (sin²A - cos²A)

{(sin²A + cos²A)² - 2 sin²A cos²A}

={sin²A - (1 - sin²A)) (1 - 2 sin²A cos²A)

= (sin²A - 1+ sin²A) (1 - 2 sin³A cos²A)

= (2 sin³A - 1) (1 - 2 sin²A cos²A)

sin³A - cos³ A

= (2 sin²A - 1) (1-2 sin²A cos²A)

Hence, proved.

Trigonometric Rules:

• sin²A + cos²A = 1

• sec²A - tan²A = 1

• cosec²A - cot²A = 1

Answered by ItzUrTanu
1

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