CBSE BOARD X, asked by 86756, 9 months ago

Sin8A/sin4A - cos8A/cos4A

Answers

Answered by debanjankrishna

2

Answer:

Sec4A

Explanation:

sin8A/sin4A-cos8A/cosa

=2sin4A.cos4A/sin4A-cos8A/cos4A

=2cos4A-cos8A/cos4A

=(2cos²4A-cos8A)/cos4A

=(2cos²4A-2cos²4A+1)/cos4A

=1/cos4A

=sec4A

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