Chemistry, asked by KalluJatt, 1 year ago

sin8A/sinA = 8cosA cos2A cos4A

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Answered by AR17
3
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Answered by pvk
1
2sin4Acos4A/sinA
4sin2Acos2Acos4A/sinA
8sinAcosAcos2Acos4A/sinA
8cosAcos2Acos4A
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