Question

sinA=1/3, find the value of cosA.cosecA+tanA.secA

Answer 1

cosA.cosecA+tanA.secA
=cosA/sinA+sinA/cos^2A
=cosA/(1/3)+sinA/(1-sin^2A)
=3cosA+3/8
=3 (cosA+1/8)
$= 3( \frac{2 \sqrt{2} }{3} + \frac{1}{8} )$
as sinA=1/3,,so cosA=(2.2^(1/2))/3

$= 2 \sqrt{2} + \frac{3}{8}$
$= 3.20343 \: \: (approximate \: value)$
I HOPE IT WILL HELP YOU.