Question

(SinA)/(1-CosA)=?

(A)(1+CosA)/(1-CosA)
(B)CosecA+CotA
(C)SinA
(D)(1+CosA)/SinA

Note:It's multi-answer question and I also need explanation​

Answer 1

Answer:

(d) (1+CosA) /SinA

1. explanations:- sinA/1-cosA*1+CosA/1+CosA=SinA(1+CosA)/1-Cos²A
2. SinA(1+CosA) /Sin²A=1+CosA/SinA