sinA/1+cosA+tanA/1+cosA=?
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0
Answer:
Soryy but math don't have / and CosA so how it will be the answer
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1
Answer:
tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosA
LHS = tanA + secA -1 / tanA - secA + 1
= tanA + secA + tan2A - sec2A / tanA - secA + 1
as tan2A + 1 = sec2A
= tanA + secA +(tanA + secA)(tanA - secA)/ tanA - secA + 1
= tanA + secA( 1 + tanA - secA) / tanA - secA + 1
=tanA + secA
= sinA / cosA + 1/cosA
= sinA + 1 / cosA
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