Question

sina/1+cota-cosa/1+tana=sina-cosa

Answer 1

$\frac{sinA}{1 +cotA} - \frac{cosA}{1 + tanA} \\ \\ = \frac{ {sin}^{2}A }{sinA + cosA} - \frac{ {cos}^{2}A }{cosA + sinA} \\ \\ = \frac{ {sin}^{2}A }{sinA + cosA} - \frac{ {cos}^{2} A}{sinA + cosA} \\ \\ = \frac{ {sin}^{2}A - {cos}^{2} A}{sinA + cosA} \\ \\ = sinA - cosA$