Question

sinA=3/5,cosB=5/13 find sin(A+B)

Answer 1

Sin A = 3/5 =>cosA = 4/5

cosB = 5/13 =>sinB = 12/13

sin(A+B) = sinAcosB + cosAsinB

= (3/5)(5/13) + (12/13)(4/5)

= 15/65 + 48/65

= 63/65

Hope it helps u :-)

Answer 2

Answer:

Step-by-step explanation:

sinA = 3/5      cosB = 5/13     sinB = 4/5   cosA = 12/13

sin [A+B] = sinAcosB + cosAsinB

               = 3/5*5/13 + 12/13*4/5  = 3/13 + 48/65

               = 15/65 + 48/65 =63/65