Question

SinA=4/5 तथा SinB=5/13 है तो sin (A+B)=?

Answer 1

Step-by-step explanation:

sinA = 4/5 thus, cos A = 3/5

and also ,

sinB = 5/13 thus, cos B = 12/13

now,

sin(A+B) = sinAcosB + cosAsinB

=

$\frac{4}{5} \times \frac{12}{13} + \frac{3}{5} \times \frac{5}{13}$

48/65 + 15/65

(48 + 15)/65

63/65 ans