Sina = a/b find cosA
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Answered by
5
Hi Friend !!!!
Here is ur answer !!!!
sinA = a/b
Opp = a
hyp = b
adj = √b² - a²
Cos A = √b²-a² / b
Hope it helps u :-)
Here is ur answer !!!!
sinA = a/b
Opp = a
hyp = b
adj = √b² - a²
Cos A = √b²-a² / b
Hope it helps u :-)
Answered by
3
hey, here is your answer...
given, sinA = a/b..
cosA = ?.,
we know that, sinA = opp.side/hyp.
and cosA = adj.side/hyp.
opp.side = a ,. hyp. = b..
let, adj. side be 'x'....
then, a^2 + x^2 = b^2....
x^2 = b^2 - a^2...
x = √(b^2 - a^2) ...
therefore, cosA = [√(b^2 - a^2)]/b.....
hope this helps you...
thank you..
plzz mark me as brainliest..
given, sinA = a/b..
cosA = ?.,
we know that, sinA = opp.side/hyp.
and cosA = adj.side/hyp.
opp.side = a ,. hyp. = b..
let, adj. side be 'x'....
then, a^2 + x^2 = b^2....
x^2 = b^2 - a^2...
x = √(b^2 - a^2) ...
therefore, cosA = [√(b^2 - a^2)]/b.....
hope this helps you...
thank you..
plzz mark me as brainliest..
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