Math, asked by sneha7095, 1 year ago

SinA=cos(A-45°) find the value of A​

Answers

Answered by Anonymous
6

SinA=cos(A-45°)

Cos(90-A)=cos(A-45)

Comparing both sides we get

90-A=A-45

2A=135

A=135/2

A=62.5°

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Answered by rockingdude
3

sinA=cos(A-45)

sinA=sin[90-(A-45)]

A=45-A (solving LHS and RHS)

A=45/2

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