Question

SinA-cosA+1/sinA+cosA-1=1/secA-tanA

Answer 1

diving by cosANUMERATOR AND DENOMENATOR
sinA/ cosA-cosA/cosA+ 1/cosA/sinA/ cosA+cosA/cosA- 1/cosA
tanA -1 +secA /tanA +1 -secA
(tanA +secA)-1/(tanA -secA)+1
{(tanA +secA)-1}(tanA -secA)/{(tanA -secA)+1}(tanA -secA)
(tanA^2+secA^2)-(tanA -secA)/{(tanA -secA)+1}(tanA -secA)
-1-tanA +secA/{(tanA -secA)+1}(tanA -secA)
-1/tanA -secA
-(1)/-(tanA +secA)
1/secA-tanA