Math, asked by abdulrahmanm774, 1 year ago

(SinA + CosA) (1-sinA cosA) = sin3A + cos3A

Answers

Answered by hazarikapapuli041
17

Answer:

Step-by-step explanation:

Attachments:
Answered by sushmita
64

Answer:

____________

⚫ sin^3A+cos^3A= (sinA+cosA)(1-sinAcosA)

Step-by-step explanation:

__________________

Formula used:

1.\:a^3+b^3=(a+b)(a^2-ab+b^2)

2.\:sin^2{\theta}+cos^2{\theta}=1

Now,

sin^3A+cos^3A

=(sinA+cosA)(sin^2A-sinA\:cosA+cos^2A) (using formula (1))

=(sinA+cosA)(sin^2A+cos^2A-sinA\:cosA)

=(sinA+cosA)(1-sinA\:cosA) (using formula (2))

Therefore,

sin^3A+cos^3A= (sinA+cosA)(1-sinAcosA)

⤴⤴⤴⤴⤴⤴⤴⤴⤴

HOPE IT HELP YOU

Similar questions