(SinA + CosA) (1-sinA cosA) = sin3A + cos3A
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⚫ sin^3A+cos^3A= (sinA+cosA)(1-sinAcosA)
Step-by-step explanation:
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Formula used:
1.\:a^3+b^3=(a+b)(a^2-ab+b^2)
2.\:sin^2{\theta}+cos^2{\theta}=1
Now,
sin^3A+cos^3A
=(sinA+cosA)(sin^2A-sinA\:cosA+cos^2A) (using formula (1))
=(sinA+cosA)(sin^2A+cos^2A-sinA\:cosA)
=(sinA+cosA)(1-sinA\:cosA) (using formula (2))
Therefore,
sin^3A+cos^3A= (sinA+cosA)(1-sinAcosA)
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