Question

sinA+cosA=1 then sinA-cosA=?​

Answer 1

Answer:

this is the answer. I hope this helps you.

Answer 2

Answer: +1 or -1

explanation : [squaring (SinA + CosA = 1) on both sides]

                    Sin(square)A + 2SinACosA + Cos(square)A = 1    (a+b whole square)

                    1 + 2SinACosA = 1     (sin square A + Cos square A = 1)

                    2SinACosA = 0  (cancel 1 on both sides)

                    2SinA * 1/SinA = 0 (cosA = 1 by SinA)

                    Sin2A = 0

                   2A = 0

                   A = 0

                   SinA-CosA = -1