Math, asked by lianpuii7emerald, 5 hours ago

(sinA + cosA) ² - (sina - cosA) ² = 4 sinA cosA

Answers

Answered by Anonymous

3

Answer:

LHS = (sinA + cosA)² - (sinA - cosA)²

= (sin²A + cos²A + 2sinAcosA) - (sin²A + cos²A - 2sinAcosA)

= (1 + 2sinAcosA) - (1 - 2sinAcosA)

= 2sinAcosA + 2sinAcosA

= 4sinAcosA

= RHS

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