(sinA.cosB-cosA.sinB(sinA.cosB+cosA.sin.sinB)=sin²A.sin²B
Answers
Answered by
3
Answer:
SinA.CosB - cosA.sinB = sin(A - B)
sinA.CosB + cosA.sinB = sin ( A + B)
substitute the value you will get the answer
Similar questions