(SinA + Cosec A)² +(CosA +SecA)² = 7+tan²A+ Cot²A.
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Answered by
5
Step-by-step explanation:
=(sinA+cosecA)²+(cosA+secA)²
=sin²A+cosec²A+2sinAcosecA+cos²A+sec²A+2cosAsecA
=sin²A+cos²A+cosec²A+sec²A+2sinA×1/sinA+2cosA×1/cosA
=1+cosec²A+sec²A+2+2
=5+(1+cot²A)+(1+tan²A)
=7+tan²A+cot²A
Identities used:
1+tan²A=sec²A
1+cot²A=cosec²A
sin²A+cos²A=1
cosecA=1/sinA
secA=1/cosA
.......
Answered by
0
Step-by-step explanation:
sinsquareA+cosecsquareA+2sinA×cosecA+cossquareA+secsquareA+2cosA×secA
sinsquareA+cossquareA+2sinAcosecA+2cosA×secA+cosecsquareA+secsquareA
1+2×1+2×1+1+cotsquareA+1+tansquareA
1+2+2+1+1+cotsquareA+tansquareA
7+tansquareA+cotsquareA
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