(sina- coseca)(cosa-seca)=1/tana+cota
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Step-by-step explanation:
Here is ur answer...
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From lhs ..
(sinA-cosecA)(cosA-secA)
=>(sinA-1/sinA)(cosA-1/cosA)
=>(sin^2A-1/sinA)*(cos^2A-1)/cosA
=>(cos^2A/sin^2A*)*(sin^2A/cosA) ...【•*•sin^2A-1=cos^2A ...and cos&2A-1=sin^2A】
=>cos^2A*sin^2A/cosA*sinA
=>cosA*sinA.......lhs...
again....from..Rhs ....
1/(tanA+cotA)
=>1/sinA/cosA+cosA/sinA
=>1/sin^2A+cos^2A/sinA*cosA.
=>1/1/sinA*cosA...【cos^2A+sin^2A=1】
so.....sinA*cosA....Rhs=lhs ....prooved...here...
Hope it helps you.✔✔✔
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