two congruent, isosceles triangles are joined, as shown, to form a parallelogram, the largest angle of the parallelogram is 116 degrees. Write two equations. Write them find the value of a and the value of b.
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Step-by-step explanation:
Given two congruent, isosceles triangles are joined, as shown, to form a parallelogram, the largest angle of the parallelogram is 116 degrees. Write two equations. Write them find the value of a and the value of b.
We know that the sum of all the internal angles is 360 degree. So the equation will be
- 4 a + 2b = 360
- According to the question the largest internal angle of the parallelogram is 116 degree. So a + b = 116
- Now we have the two equations as
- 4a + 2b = 360
- a + b = 116
- Multiply the second equation by 4 we get
- 4a + 2b = 360
- 4a + 4b = 464
- Or – 2b = - 104
- Or b = 52
- Now a + b = 116
- Or a + 52 = 116
- Or a = 116 – 52
- Or a = 64
Therefore the values of a and b are 64 and 52 degrees
Reference link will be
https://brainly.in/question/13950918
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Answer: a 64 b 52
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