(sinA/cosecA-cotA)+(sinA/cotA+cosecA)=2.
how? plz help me with this. I will mark it as brainalist.
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Answer:
Step-by-step explanation:
sinA/cotA+cosecA
=sinA/(cosA/sinA+1/sinA)
=sinA/{(cosA+1)/sinA}
=sin²A/(1+cosA)
=(1-cos²A)/(1+cosA)
=(1+cosA)(1-cosA)/(1+cosA)
=1-cosA
2+sinA/cotA-cosecA
=2+sinA/(cosA/sinA-1/sinA)
=2+sinA/{(cosA-1)/sinA}
=2+sin²A/(cosA-1)
=2+(1-cos²A)/{-(1-cosA)}
=2-(1+cosA)(1-cosA)/(1-cosA)
=2-(1+cosA)
=2-1-cosA
=1-cosA
∴, LHS=RHS (Proved)
plz mark me as brainalist.
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