Math, asked by bharathreddy2008, 11 hours ago

(sinA+cotA)^2 (sinA-cotA) ^2 =?

Answers

Answered by pratyush1910

0

cotA+cscA

sinA

=2+

cotA−cscA

sinA

∴

cotA+cscA

sinA

−

cotA−cscA

sinA

−2=0

∴LHS=

cot

2

A−csc

2

A

sinA(cotA−cscA)−sinA(cotA+cscA)

=

(−1)

sinA(cotA−cscA−cotA−cscA)

=

(−1)

sinA(−2cscA)

=+2

=RHS

PLEASE MARK ME AS BRAINLIST

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