sina=root3(1-cosa) solve it
Answers
Answered by
1
Answer:
sina = √3 ( 1- cosa)
squaring
sin^2 a = 3 ( 1-cosa)^2
sin^2 a = 3 ( 1+ cos^2a - 2cosa)
As sin^2a = 1- cos^2 a
1- cos^2a = 3 + 3 cos^2a - 6cosa
4cos^2a - 6cos a + 2 = 0
2 cos^2 a - 3cosa +1= 0
2 cos^2a - 2cos a - cos a +1= 0
2cosa (cosa -1) -( cosa -1)=0
( 2 cos a -1)( cosa -1)=0
cosa = 1, 1/2
a = 2nΠ , 2nΠ+- Π/3
#answerwithquality #BAL
Answered by
1
Answer:
sina = √3 ( 1- cosa)
squaring
sin^2 a = 3 ( 1-cosa)^2
sin^2 a = 3 ( 1+ cos^2a - 2cosa)
As sin^2a = 1- cos^2 a
1- cos^2a = 3 + 3 cos^2a - 6cosa
4cos^2a - 6cos a + 2 = 0
2 cos^2 a - 3cosa +1= 0
2 cos^2a - 2cos a - cos a +1= 0
2cosa (cosa -1) -( cosa -1)=0
( 2 cos a -1)( cosa -1)=0
cosa = 1, 1/2
a = 2nΠ , 2nΠ+- Π/3
Similar questions