Question

(Sina +seca)2 + (cosa +coseca)2=(1+cosecaseca)2

Answer 1

heya it's Aastha....

◆ Taking LHS.

(sinA + secA)2 +( cosA + CosecA)2

= sin2A +sec2A +2sinAsecA +cos2A +cosec2A +2cosAcosecA

= (sin2A + cos2A)  + (sec2A +cosec2A) +( 2sinA/cosA + 2cosA/sinA)

=1 + (1/cos2A + 1/sin2A) + ( 2sin2A +2cos2A/sinAcosA)

=1 +(sin2A +cos2A/sin2Acos2A) +[ 2(sin2A+cos2A) / sinAcosA]

=1 + 1/sin2Acos2A + 2/sinAcosA

= (1 + 1/sinAcosA)2

= (1 + cosecAsecA)2

=RHS .
Hence proved.

I hope it help you

Answer 2

Hey....your answer goes here.....
Hope it's helpful to u....☺☺☺