Question

sinA.sin(A+B)is equal to

Answer 1

as it is given= sinA.sin(A+B)
 by using Sin(A+B)=sinAcosB+cosAsinB
  ⇒sinA(sinAcosB+cosAsinB)
∴sinA.sin(A+B)=sin²AcosB+sinAcosAsinB

Answer 2

Answer:

sinAsin(A+B)

sinAsin(A+B)=sin²AcosB+sinAcosAsinB

Step-by-step explanation:

SinAsin(A+B)

________________________

We know that,

$\boxed {sin(A+B)\\=sinAcosB+cosAsinB}$

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=sinA(sinAcosB+cosAsinB)

= sin²AcosB+sinAcosAsinB

Therefore,

sinAsin(A+B)

=sin²AcosB+sinAcosAsinB

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