Question

sinA +sin3A /cosA +cos2A =tan2A

Answer 1

Hey dear here is ur answer *******
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$\sin( \alpha ) + \sin(3 \alpha ) \div \cos( \alpha ) + \cos(2 \alpha )$

={2× sin2 alpha×cos alpha}÷{2×cos2 alpha×cos alpha}

=tan 2 alpha. [proved]

Hope it will help u@@###