Question

Sina + Sinb =√3
P.T tana + tanb = 1

Answer 1

Here is your answer mate:-

If tanA = 1; tanB = √3 therefore, A is equal to 45 degree and B is equal to 60 degree hence, tan 45 degree is equal to 1 and tan 60 degree is equal to √3 Solution 1 – cos A.cos B – sin A.sinB which is equal to, (cos 45 degree) (cos 60 degree) - (sin 45 degree) (sin 60 degree) which is, 1/2 x 1/√2 - 1/√2 x √3/2 = 1-√3/2√2

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Answer 2

Here is your answer mate:-

If tanA = 1; tanB = √3 therefore, A is equal to 45 degree and B is equal to 60 degree hence, tan 45 degree is equal to 1 and tan 60 degree is equal to √3 Solution 1 – cos A.cos B – sin A.sinB which is equal to, (cos 45 degree) (cos 60 degree) - (sin 45 degree) (sin 60 degree) which is, 1/2 x 1/√2 - 1/√2 x √3/2 = 1-√3/2√2

hope it helps u mate

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