Question

Sina=sinb a+b =90 prove that

Answer 1

Answer:

HERE THE ANSWER

Left hand side ...Put B= 90 - A .....

(SinA + sin (90 - A ) ) / sinA =( sinA + cos A )/sinA ....

= 1 + cotA .....

Right hand side ....similarliy .....

tanA + 2tan( 90 - A ) = tanA + 2 cot A .

........

= 1 + cot A .....

Hence both side are equal .....

Proved ......

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