Sina+sinb+sinc=0 cosa+cosb+cosc=0 then what is the value of cos3a+cos3b+cos3c?
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CosA+cosB+cosC=0 (given)
To find :- 3cosA+3cosB+3cosC=?
3cosA+3cosB+3cosC
3(cosA+cosB+cosC)
3(0) (bcz:-cosA+cosB+cosC=0)
=0
Therefore :- 3cosA+3cosB+3cosC=0
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