Math, asked by yogesh69, 1 year ago

sinA+sinB+sinC=3 tjen find cosA+cosB+cosC

Answers

Answered by Bhaavya1
1
angle A, B ,C are 90°

sin90°=1
sin90 + sin90 + sin90=1+1+1=3

so, cos 90+cos 90+ cos 90=0+0+0
=0

hope u got it

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