sinA+sinB+sinC=3 tjen find cosA+cosB+cosC
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angle A, B ,C are 90°
sin90°=1
sin90 + sin90 + sin90=1+1+1=3
so, cos 90+cos 90+ cos 90=0+0+0
=0
hope u got it
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sin90°=1
sin90 + sin90 + sin90=1+1+1=3
so, cos 90+cos 90+ cos 90=0+0+0
=0
hope u got it
plzz mark it brainliest
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