Question

sin@=a/b then find cos@​

Answer 1

Sin @=a/b=p/h

According to pythagoras theorem,

b=√h^2 - p^2

=√b^2-a^2

We know,

Cos @=b/h=√b^2-a^2/b

Answer 2

Sin @=a/b=p/h

According to pythagoras theorem,

b=√h^2 - p^2

=√b^2-a^2

We know,

Cos @=b/h=√b^2-a^2/b