sin@=a/b then find cos@
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Sin @=a/b=p/h
According to pythagoras theorem,
b=√h^2 - p^2
=√b^2-a^2
We know,
Cos @=b/h=√b^2-a^2/b
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Sin @=a/b=p/h
According to pythagoras theorem,
b=√h^2 - p^2
=√b^2-a^2
We know,
Cos @=b/h=√b^2-a^2/b
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