Question

Sine squire30+sine squire45+sine squire60

Answer 1

${ \sin }^{2} 30\degree + { \sin}^{2} 45\degree + { \sin}^{2} 60\degree \\ = {( \frac{1}{2} )}^{2} + {( \frac{1}{ \sqrt{2} } )}^{2} + { (\frac{ \sqrt{3} }{2}) }^{2} \\ = \frac{1}{4} + \frac{1}{2} + \frac{3}{4} \\ = \frac{1 + 2 + 3}{4} \\ = \frac{6}{4} \\ = \frac{3}{2}$

HOPE IT'LL HELP....

Answer 2

$\sin {}^{2} (30) + \sin {}^{2} (45) + \sin {}^{2} (60) \\ = ( \frac{1}{2} ) {}^{2} + ( \frac{1}{ \sqrt{2} }) {}^{2} + (\frac{ \sqrt{3} }{2} ) {}^{2} (putting \: the \: value \: of \: \sin(30) \sin(45) \: \sin(60) \\ = \frac{1}{4} + \frac{1}{2} + \frac{3}{4} \\ \frac{6}/$

= 3/2