Question

Sinq=12/13 and q is acute then tanq

Answer 1

sin q = 12/13 = height/hypotenuse

 

Let height be 12x and hypotenuse be 13x


By Pythagoras Theorem, 

Base^2 = (13x)^2 - (12x)^2 
             = 169x^2 - 144x^2
             = 25x^2

Base     = 5x 


======================

tanq = height/base 

       = 12x/5x 

       = 12/5 






i hope this will help you



(-:

Answer 2

Heya !!!





Sin Q = 12/13 = P/H




P = 12 and H = 13




By Pythagoras theroem ,



(H)² = (B)² + (P)²




(B)² = (H)² - (P)²




(B)² = (13)² - (12)²




(B)² = 169 - 144




B = ✓25 = 5




Tan Q = P/B = 12/5






★ HOPE IT WILL HELP YOU ★