Question

∫sinx /3+5cos x [integration class 12 ISC]
solve ? ​

Answer 1

Answer:

Integral (sinx/3+5cosx) dx

Put 3+5cos x = u

Differentiating both sides,

-5 sin x dx = du

which means,

sin x dx = -1/5 du

So, integral changes to

Integral (1/u)(-du/5) = -1/5 Integral du/u = -1/5 ln |u| + c

= -1/5 ln |3+5cos x | + c

Hope this helps you ! :)

Answer 2

Answer:

$\huge{ \color{lime}- \frac15 \: \: \log |3+5cosx| +c }$

Step-by-step explanation:

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