Question

Sinx = Cos2x, then the value of Cos2x(1+Cos2x) will be​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

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Sinx = Cos2x, then the value of Cos2x(1+Cos2x) will be

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GIVEN:

Given, sinx=cos 2 x

Given, sinx=cos 2 xThus sinx=1−sin 2 x

Given, sinx=cos 2 xThus sinx=1−sin 2 x⇒sin 2

Given, sinx=cos 2 xThus sinx=1−sin 2 x⇒sin 2 x+sinx=1 ....(1)

Given, sinx=cos 2 xThus sinx=1−sin 2 x⇒sin 2 x+sinx=1 ....(1)We need to find value of cos

Given, sinx=cos 2 xThus sinx=1−sin 2 x⇒sin 2 x+sinx=1 ....(1)We need to find value of cos 2 x(1+cos 2 x)

Given, sinx=cos 2 xThus sinx=1−sin 2 x⇒sin 2 x+sinx=1 ....(1)We need to find value of cos 2 x(1+cos 2 x)⇒sinx(1+sinx)

Given, sinx=cos 2 xThus sinx=1−sin 2 x⇒sin 2 x+sinx=1 ....(1)We need to find value of cos 2 x(1+cos 2 x)⇒sinx(1+sinx)⇒sinx+sin 2 x

Given, sinx=cos 2 xThus sinx=1−sin 2 x⇒sin 2 x+sinx=1 ....(1)We need to find value of cos 2 x(1+cos 2 x)⇒sinx(1+sinx)⇒sinx+sin 2 xFrom the equation (1), we have

Given, sinx=cos 2 xThus sinx=1−sin 2 x⇒sin 2 x+sinx=1 ....(1)We need to find value of cos 2 x(1+cos 2 x)⇒sinx(1+sinx)⇒sinx+sin 2 xFrom the equation (1), we havesinx+sin 2

Given, sinx=cos 2 xThus sinx=1−sin 2 x⇒sin 2 x+sinx=1 ....(1)We need to find value of cos 2 x(1+cos 2 x)⇒sinx(1+sinx)⇒sinx+sin 2 xFrom the equation (1), we havesinx+sin 2 x=1

Option B is correct.