Math, asked by sakshamsingh2544, 10 months ago

Sinx-cosx+1/sinx+cosx-1=tanx+secx

Answers

Answered by sandy1816

1

Step-by-step explanation:

sinx-cosx+1/sinx+cosx-1

devide by cosx in each term

tanx+secx-1/tanx-secx+1

=(secx+tanx)-(sec²x-tan²x)/tanx-secx+1

=(secx+tanx)(1-secx+tanx)/(tanx-secx+1)

=secx+tanx

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