Math, asked by prashantgurjar293, 3 months ago

sinx.cosx
find the derivative ​

Answers

Answered by kanishkaverma1952
3

HELLO EVERYONE,

let f(x) =sinx.cos(x)

d{f(x) }/dx= 1st.function.d/dx.2nd.function+2nd.function.d/dx1st.function

d{f(x) }/dx= sinx(-sinx) +cosx(cosx)

=-sin²x+cos²x

d{f(x) }/dx=cos2x [cos²x-sin²x=cos2x]

I HOPE YOU LIKE IT.

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