sinx.cosx
find the derivative
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HELLO EVERYONE,
let f(x) =sinx.cos(x)
d{f(x) }/dx= 1st.function.d/dx.2nd.function+2nd.function.d/dx1st.function
d{f(x) }/dx= sinx(-sinx) +cosx(cosx)
=-sin²x+cos²x
d{f(x) }/dx=cos2x [cos²x-sin²x=cos2x]
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