Math, asked by happyreader84, 1 year ago

sinx ×sec(90-x)×tanx/cosec(90-x)×cosx×cot(90-x)

Answers

Answered by rupammula3
1

Answer:


Step-by-step explanation:

Sinx*sec(90°-x)*tanx/cosec(90°-x)*cosx*cot(90°-x)

=sinx*cosecx*tanx/secx*1/secx*tanx

=sinx*1/sinx*secx/cosecx*1/secx*1/secx*secx/cosecx

=1/cosecx*1/cosecx

=sin^2x

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